0=1.8+22.52x-4.9x^2

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Solution for 0=1.8+22.52x-4.9x^2 equation:



0=1.8+22.52x-4.9x^2
We move all terms to the left:
0-(1.8+22.52x-4.9x^2)=0
We add all the numbers together, and all the variables
-(1.8+22.52x-4.9x^2)=0
We get rid of parentheses
4.9x^2-22.52x-1.8=0
a = 4.9; b = -22.52; c = -1.8;
Δ = b2-4ac
Δ = -22.522-4·4.9·(-1.8)
Δ = 542.4304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22.52)-\sqrt{542.4304}}{2*4.9}=\frac{22.52-\sqrt{542.4304}}{9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22.52)+\sqrt{542.4304}}{2*4.9}=\frac{22.52+\sqrt{542.4304}}{9.8} $

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